A circular insulated copper wire loop is twisted to form two loops of are A and 2A as shown in the figure. At the point of crossing the wires remain electrically insulated from each other. The entire loop lies in the plane ( of the paper). A uniform magnetic vecB point into the plane of the paper . At t=0, the loop starts rotation about the common diameter as axis with a constant angular velocity omega in the magnetic field. Which of the following options is /are correct ?

A circular insulated copper wire loop is twisted to form two loops of

1.	A circular insulated copper wire loop is twisted to form two loops of are A and 2A as shown in the figure. At the point of crossing the wires remain electrically insulated from each other. The entire loop lies in the plane ( of the paper). A uniform magnetic vecB point into the plane of the paper . At t=0, the loop starts rotation about the common diameter as axis with a constant angular velocity omega in the magnetic field. Which of the following options is /are correct ?
Answer» The NET emf induced due to both the LOOPS is proportional to `cos omega t` The rate of change of the FLUX is maximum when the PLANE of the loops is perpendicular to plane of the paper The amplitude of the maximum net emf induced due to both the loops is equl to the amplitude of maximum emf induced in the smaller loop ALONE The emf indued in the loop is proportional to the sum of the area of the two loops. Answer :B::C

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