A circular flower bed is surrounded by a path 4 m wide. The diameter o

1.	A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path? (π = 3.14)
Answer» $\huge\tt \underline \red{Question}$ A CIRCULAR flower bed is surrounded by a path 4 m WIDE. The diameter of the flower bed is 66 m. What is the area of this path? (π = 3.14) $\rm \underline \red{Given \: :}$ Diameter of flower bed. Radius of path surrounded by flower bed. $\rm \underline \red{To \: <klux>FIND</klux> \ :}$ Area of path. $\huge\rm \underline \red{Solution╭☞}$ First, find area of flower bed↓ Radius $= \frac{66}{2} = 33m$ Area of flower bed $\red{ = \pi r {}^{2} }$ $= 3.14 \times 33 \times 33$ $= 3.14 \times 1089$ $= 3419.46 {m}^{2}$ Now, We'll find area of Path ↓ Radius of circle 2 $\sf { \{Radius \: of \: inner \: circle + Radius \: of \: path} \}$ $= (33 + 4) = 37$ Area of circle 2 $\red{= \pi r {}^{2} }$ $= 3.14 \times 37 \times 37$ $= 3.14 \times 1369$ $= 4298.66 {m}^{2}$ So, Now Area of path (SHADED region) = Area of Circle 2 - Area of flower bed $\fbox{4298.66 - 3414.46}$ $\fbox{ = 879.2 m²}$ Hence, Area of path is 879.2m². Hope It Helps You! ツ