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| 1. |
A circular disc of radius b has a hole of radius a at its centre (see figure). If the mass per unit area of the disc varies as (σ₀/r) then the radius of gyration of the disc about its axis passing through the centre is :(A) (a + b)/3(B) √[(a² + b² + ab)/3](C) (a + b)/2(D)√[(a² + b² + ab)/2] |
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