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A circular disc of radius `0.2 m` is placed in a uniform magnetic fied of induction `(1)/(pi) ((Wb)/(m^(2)))` in such a way that its axis makes an angle of `60^(@)` with The magnetic flux linked with the disc isA. 0.02WbB. 0.06WbC. 0.08WbD. 0.01Wb |
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Answer» Correct Answer - A Here, `r=0.2m,B=(1)/(pi)Wbm^(-2),theta=60^(@)` `:.` Magnetic flux, `phi=BAcostheta=B(pir^(2))costheta` `(1)/(pi)pi(0.2)^(2)cos60^(@)=0.02Wb` |
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