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A circular disc of radius 0.1 m and mass 1 kg is rotating at the rate of 10 rps about its axis . Find the work that must be done to increase the rate of revolution to 20 rps |
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Answer» Answer: EXPLANATION as the OBJECT is moving in circular PATH PE is 0 So TE= KE KE (1)=1/2*1*10*10 =50J KE (2)=1/2*1*20*20 =200J Therefore,work done =200-50=150J |
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