A circular disc of mass 2 kg is placed over a rough horizontal surface. Coefficient of friction is 0.5. A force F is applied on the periphery of the disc, tangentially in vertically downward direction. The disc will undergo pure rolling only if F≤F0. When F=F0, the value of F0 in N is (Take g=10 m/s2) (Answer upto two digit after decimal place)

A circular disc of mass 2 kg is placed over a rough horizontal surface

1.	A circular disc of mass 2 kg is placed over a rough horizontal surface. Coefficient of friction is 0.5. A force F is applied on the periphery of the disc, tangentially in vertically downward direction. The disc will undergo pure rolling only if F≤F0. When F=F0, the value of F0 in N is (Take g=10 m/s2) (Answer upto two digit after decimal place)
Answer» A circular disc of mass $2 k g$ is placed over a rough horizontal surface. Coefficient of friction is $0.5$ . A force F is applied on the periphery of the disc, tangentially in vertically downward direction. The disc will undergo pure rolling only if $F \leq F_{0} .$ When $F = F_{0}$ , the value of $F_{0}$ in $N$ is (Take $g = 10 m / s^{2}$ ) (Answer upto two digit after decimal place)

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