1.

a circular coil of radius r and current i the magnetic inductionat a point on a axis of the coil at a distance 2√2r from its centre will be​

Answer»

>

We know that at the axis of a CURRENT carrying coil at distance x from the center , magnetic field B is given by-

B

1

=

2(R

2

+x

2

)

3

/2

μ

o

IR

2

And B=

2R

μ

o

I

B

1

=

8

B

2(R

2

+x

2

)

3

/2

μ

o

IR

2

=

16R

μ

o

I

⟹8R

3

=(R

2

+x

2

)

3/2

⟹2R=(R

2

+x

2

)

1/2

⟹4R

2

=R

2

+x

2

⟹x

2

=3R

2

⟹x=R

3


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