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A circular coil of radius 10cm and 25 turns is rotated about its vertical diameter with an angular speed of 40rads^(-1), in a uniform horizontal magnetic field of magnitude 5xx10^(-2)T. Calculate the maximum emf induced in the coil. Also find the maximum current in the coil if the resistance of the coil is 15Omega. |
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Answer» SOLUTION :Emf induced in the coil =`EPSILON=nAB omegasin (omegat)=epsilon_0 sin omegat` Area = `pir^2` `epsilon=(25xx3.14xx10xx10^(-2)xx10xx10^(-2)xx5xx10^(-2)xx40)sin (40t)` `epsilon` = 1.57 sin 40 t `epsilon_0`=1.57 Volt `I=epsilon/R =(1.57(sin 40t)V)/15, I_(max)=epsilon_0/R= (1.57V)/(15Omega)` = 0.1047 A = 0.11 A Current `I_(INST)`=0.1047 sin 40t A `I_(max)`=0.11 A |
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