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A circular coil having N turns and radius r carries a current. It is held in the XZ plane in a magnetic field Bî. The torque on the coil due to the magnetic field is: (A) Br²1/πN(B) zero (C)Bπr²1/N(D) Bπr²IN |
Answer» ANSWER:CORRECT Option is : (D ). TORQUE = NIπr²B Explanation :Torque = NIAB sin ¢ Here, ¢ = 90° Torque = NIπr²B |
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