1.

A circular coil having N turns and radius r carries a current. It is held in the XZ plane in a magnetic field Bî. The torque on the coil due to the magnetic field is: (A) Br²1/πN(B) zero (C)Bπr²1/N(D) Bπr²IN

Answer»

ANSWER:

CORRECT Option is :

(D ). TORQUE = NIπr²B

Explanation :

Torque = NIAB sin ¢

Here, ¢ = 90°

Torque = NIπr²B



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