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| 1. |
A circular arc of length `pi` cm. Find angle subtended by it at the centre in radian and degree. |
| Answer» `theta= (s)/(r) = (pi" cm ")/(6" cm")= (pi)/(6) rad= 30^(@)` As 1 rad`= (180^(@))/(pi)` So `theta = (pi)/(6)xx (180^(@))/(pi)= 30^(@)` | |