1.

A circuit delivers energy at the rate of 20W and the current is 10A. Determine the energy of each coulomb of charge in the circuit.

Answer»

Given:-

I = 10

P= 20

Q = 1

⇒P = V × I

⇒ V = \(\frac{P}{I}\)\(\frac{20}{10}\) = 2V

W = VQ = 2 × 1= 2J 

The energy of each coulomb of charge in the circuit is 2J

From equation: 

P = VI

V = P/I ​= 20/10 ​= 2V

From equation:

V = W/Q

W = VQ 

= 2 × 1 

= 2J



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