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A circuit containing an 80 mH inductor and a `250 mu F` capacitor in series is connected to 240 V, `100 rad//s` supply. The resistance of the circuit is negligible. (i) Obtain rms value of current. (ii) What is the total average power consumed in the circuit ? |
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Answer» Here, `L = 80 mH = 80 xx 10^(-3) H`, `C = 250 mu F = 250 xx 10^(-6) F, E_(v) = 240 V`, `omega = 100 rad//s` `X_(L) = omega L = 100 xx 80 xx 10^(-3) H = 8 Omega` `X_(C ) = (1)/(omega C) = (1)/(100 xx 250 xx 16^(-6)) = 40 Omega` `Z = X_(C ) -X_(L) = 40 - 8 = 32 Omega` `I_(v) = (E_(v))/(Z) = (240)/(32) = 7.5 A` As `R = 0`, therefore power cosume is zero. |
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