Saved Bookmarks
| 1. |
A circuit consists of a resistance 10 ohm and a capacitance of `0.1 mu F` If an alternating e.m.f. of 100 V. 50 Hz is applied, calculate the current in the circuit. |
|
Answer» Here, `R = 10 ohm`, `C = 0.1 mu F = 10^(-7) F`, `E_(v) = 100 V, v = 50 Hz, I_(v) = ?` `X_(C ) = (1)/(omega C) = (1)/(2 pi v C) = (1)/(2 pi xx 50 xx 10^(-7))` `= (10^(5))/(pi) = 3.18 xx 10^(4) Omega` `Z = sqrt(R^(2) + X_(C )^(2)) = sqrt(10^(2) + (3.18 xx 10^(4))^(2))` `= 3.18 xx 10^(4)` `I_(v) = (E_(v))/(2) = (100)/(3.18 xx 10^(4)) = 3.142 xx 10^(-3) A` |
|