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A circuit `ABCD` is held perpendicular to the uinform magnetic field of `B = 5 xx 10^(-2)T` extending over the region `PQRS` and directed into the plane of the paper. The cicuit is moving out of the field at a uin form speed of `0.2 m s^(-1)` for `1.5 s`. During this time, the current in the `5 Omega` resistor is A. (a) `0.6mA from B to C`B. (b) `0.9mA from B to C`C. ( c) `0.9mA from C to B`D. (d) `0.6mA from C to B` |
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Answer» Correct Answer - A (a) `I = (Blv)/( R)` `I = (5 xx 10^(-2) xx 0.3 xx 0.2)/(5)A = 0.6 mA`. Area and flux are decreasing. So, current flows to increase the flux. Clearly, current should be clockwise. So, it flows from `B to C` through `5 Omega`. |
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