A circle passes through the points of intersection of the parabola y+1=(x–4)^2 and x-axis.Then the length of tangent from origin to the circle is

A circle passes through the points of intersection of the parabola y+1

1.	A circle passes through the points of intersection of the parabola y+1=(x–4)^2 and x-axis.Then the length of tangent from origin to the circle is
Answer» 8 15 `SQRT8` `sqrt15` Solution :`(y+1)=(x-4)^2` Put y =0 `(x-4)^2=1` x-4=1 (OR) x-4=-1 x=5 (OR) x=3 `OT^2=OA.OB` `OT^2=3xx5` `RARR OT=sqrt15`

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A circle passes through the points of intersection of the parabola y+1=(x–4)^2 and x-axis.Then the length of tangent from origin to the circle is

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