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A circle of 2.5 meter radius is made using a wire of uniform cross section and resistivity 1 m^(2). If resistance of this wire is 10 pi Omegaresistivity of the material of the wire is ........ |
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Answer» `4 pi Omega` m `R = (l rho)/(A)"" therefore R = (2 pi r rho)/(A)` `therefore rho = (RA)/(2 pi r)=(10 pi xx 1 )/(2pi xx 2.5) = 2 Omega` m |
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