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A circle is drawn with the line joining (2, 3) and (6, 5) as diameter. What are the coordinates of the centre of the circle? |
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Answer» Midpoint of the line joining (2, 3) and (6, 5) is \((\frac{x_1+x_3}{2},\frac{y_1+y_3}{2})=(\frac{2+6}{2},\frac{3+5}{2})\) \((\frac{8}{2},\frac{8}{2})=(4,4)\) ∴ Centre of the circle is (4,4) |
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