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A circle C whose radius is 1 unit, touches the x-axis at point A. The centre Q of C lies in first quadrant. The tangent from origin O to the circie touches it at T and a point P lies on it such that `DeltaOAP` is a right angled triangle at A and its perimeter is 8 units. The length of `QP` isA. `(x-2)^(2)+(y-1)^(2)=1`B. `{x-(sqrt(3)-sqrt(2))}^(2)+(y-1)^(2)=1`C. `(x-sqrt(3))^(2)+(y-1)^(2)=1`D. none of these |
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Answer» Correct Answer - 1 Now,` OA=2.` So, center of the circle is `Q (2,1)` Equation of circles is `( x-2)^(2)+ (y -1)^(2)=1` |
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