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A chord PQ of a circle with radius 15 cm subtends an angle of 60° with thecentre of the circle. Find the area of the minor as well as the major segment.(n = 3.14, V3 = 1.73) |
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Answer» Step-by-step EXPLANATION: Area of the minor SECTOR=°/360×2πr =60/360×2×3.14×15 =1/6×2×3.14×15 =15.7 Area of circle =πr² =3.14×15² 706.5 Area of major sector =area of circle -area of minor arc =690.8 Plsss mark as branliest |
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