1.

A chord PQ of a circle with radius 15 cm subtends an angle of 60° with thecentre of the circle. Find the area of the minor as well as the major segment.(n = 3.14, V3 = 1.73)​

Answer»

ANSWER:

Step-by-step EXPLANATION:

Area of the minor SECTOR=°/360×2πr

=60/360×2×3.14×15

=1/6×2×3.14×15

=15.7

Area of circle =πr²

=3.14×15²

706.5

Area of major sector =area of circle -area of minor arc

=690.8

Plsss mark as branliest



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