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A chord of circle of 10cm subtendsa right angle at its centre. the length of chord is |
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Answer» ong>Step-by-step explanation: Let r be the radius of the circle and θ be the ANGLE subtended by the chord at the center. Given: r=10 cm, θ=90 o
Length of the chord = 2rsin 2 θ
=2×10sin 2 90
=20×sin45 o
=20× 2
1
=10 2
≈14.14 cm solution please MARK me as a BRAINLIST |
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