A chord of 24 cm length is drawn in a circle of radius 13 cm. The di

1.	A chord of 24 cm length is drawn in a circle of radius 13 cm. The distance of chord from center of circle is –(a) 12 cm(b) 5 cm(c) 6.5 cm(d) 12 cm
Answer» Answer is (b) 5 cm AM = BM = \(\frac { 1 }{ 2 }\) × AM = \(\frac { 1 }{ 2 }\) × 24 = 12 cm In right ∆OAM OA² = AM² + OM² (13)² = (12)² + (OM)² OM² = (13)² – (12)² = 169 – 144 OM² = 25 OM = \(\sqrt { 25 }\) = 5 cm Thus, distance of chord from center of circle = 5 cm.

A chord of 24 cm length is drawn in a circle of radius 13 cm. The distance of chord from center of circle is –(a) 12 cm(b) 5 cm(c) 6.5 cm(d) 12 cm

Answer»

Answer is (b) 5 cm

AM = BM = \(\frac { 1 }{ 2 }\) × AM = \(\frac { 1 }{ 2 }\) × 24 = 12 cm

In right ∆OAM

OA² = AM² + OM²

(13)² = (12)² + (OM)²

OM² = (13)² – (12)² = 169 – 144

OM² = 25

OM = \(\sqrt { 25 }\) = 5 cm

Thus, distance of chord from center of circle = 5 cm.

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A chord of 24 cm length is drawn in a circle of radius 13 cm. The distance of chord from center of circle is –(a) 12 cm(b) 5 cm(c) 6.5 cm(d) 12 cm

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