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A choke of 0.5 H, a capacitor of `15 mu F` and resistance of 100 ohm are connected in series across 200 V, 50 Hz main. Find current in the circuit and power factor of the circuit. |
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Answer» Here, `L = 0.5 H, C = 15 xx 10^(-6) F, R = 100 ohm` `E_(v) = 200 V, v = 50 Hz, I_(v) = ?` power factor? `X_(L) = omega L = 2 pi v L = 2 pi xx 50 xx 0.5 = 157 Omega` `X_(C ) = (1)/(omega C) = (1)/(2 pi v C) = (1)/(2 pi xx 50 xx 15 xx 10^(-6))` `= 2.12 xx 10^(2) ohm = 212 Omega` `Z = sqrt(R^(2) + (X_(C ) - X_(L))^(2))` `= sqrt(100^(2) + (212 - 1578)^(2))` `= sqrt(100^(2) + 55^(2)) = 114.127 Omega` `I_(v) = (E_(v))/(Z) = (202)/(114.127) = 1.752 A` Power factor, `cos phi = (R )/(Z) = (100)/(114.127) = 0.876` |
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