A child pulls a Box with a force of 200 N and an angle of 60° above t

1.	A child pulls a Box with a force of 200 N and an angle of 60° above the horizontal. Then the horizontal and vertical components of the forces are
Answer» Since we are given the angle the plane makes with the horizontal, we can get the horizontal and vertical COMPONENTS using trigonometric RATIOS. The 200 N is the HYPOTENUSE magnitude. SIN 60° = Vertical / 200N Vertical = 200 × Sin 60 200 × 0.8660 = 173.2 N Horizontal = 200 × Cos 60° 200 × 0.5 = 100 N

A child pulls a Box with a force of 200 N and an angle of 60° above the horizontal. Then the horizontal and vertical components of the forces are

Answer»

Since we are given the angle the plane makes with the horizontal, we can get the horizontal and vertical COMPONENTS using trigonometric RATIOS.

The 200 N is the HYPOTENUSE magnitude.

SIN 60° = Vertical / 200N

Vertical = 200 × Sin 60

200 × 0.8660 = 173.2 N

Horizontal = 200 × Cos 60°

200 × 0.5 = 100 N

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A child pulls a Box with a force of 200 N and an angle of 60° above the horizontal. Then the horizontal and vertical components of the forces are

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