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A chemist opened a cupboard to find four bottles containing water solutions, each of twhich had lost its lable. Bottles 1,2,3 contained colourless solutions , while bottle 4 contained coloured solution. They were, Copper (II) sulphate, Hydrochloric acid. Lead nitrate, Sodium carbonate. By mixing samples of the contents of the bottles, in pairs. The chemist made the following observations, Bottle `1+` Bottle 2 white precipitate Bottle `1=` Bottle 3 white precipitate Bottle `1+` Bottle 4 white precipitate Bottle `2+` Bottle 3 colour less gas evolved Bottle `2+` Bottle 4 no visible reaction Bottle `3+` Bottle 4 blue precipitate. When bottle 1 is mixed with bottle 4, white precipitate is observed, which is `:`A. `PbSO_(4)`B. `PbCO_(3)`C. `PbCl_(2)`D. `Pb(NO_(3))_(2)`

Answer» Correct Answer - 1
`Pb(NO_(3))_(2)+CuSO_(4)rarrCu(NO_(3))_(2)+PbSO_(4)`


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