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A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 `to` White precipitate is formed. Bottle 1 +Bottle 3 `to` White precipitate is formed. Bottle 1 +Bottle 4 `to` White precipitate is formed. Bottle 2 +Bottle 3 `to` Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 `to` No visible reaction is observed. Bottle 3 +Bottle 4 `to` Blue precipitate is formed. With the help of the above observations answer the following questions. Which of the following statements is correct for salts contained in bottle 1 and 4 ?A. Bottle 4 gives white precipitate with excess of KI solutionB. Bottle 4 gives white precipitate with excess of `K_4 [Fe (CN)_6]` solutionC. Bottle 1 and 4 both gives precipitate with excess of NaOH solutionD. Bottle 1 gives white precipitate with concentrated HCl solution |
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Answer» Correct Answer - A (A)`2Cu^(2+)+4I^(-)toCu_2I_2 darr ("white")+I_2` (B)`2Cu^(2+)+[Fe(CN)_6]^(4-)toCu_2[Fe(CN)_6]darr` (chocolate brown) (C )`Pb^(2+)+4OH^(-)to[Pb(OH)_4]^(2-)`(colourless soluble complex) , `Cu^(2+)+2OH^(-)toCu(OH)_2darr`(blue) (D)`Pb^(2+)+4Cl^(-)to[PbCl_4]^(2-)darr` (colourless soluble complex) |
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