A chemist has one solution containing 50% acid and a second one contai

1.	A chemist has one solution containing 50% acid and a second one containing 25% acid. How much of each should be used to make 10 litres of a 40% acid solution?
Answer» Let x litres and y litres be the amount of acids from 50% and 25% acid solutions respectively. As per the question 50% of x + 25% of y = 40% of 10 ⇒ 0.50x + 0.25y = 4 ⇒ 2x + y = 16 ………(i) Since, the total volume is 10 liters, so x + y = 10 Subtracting (ii) from (i), we get x = 6 Now, putting x = 6 in (ii), we have 6 + y = 10 ⇒ y = 4 Hence, volume of 50% acid solution = 6litres and volume of 25% acid solution = 4litres.

A chemist has one solution containing 50% acid and a second one containing 25% acid. How much of each should be used to make 10 litres of a 40% acid solution?

Answer»

Let x litres and y litres be the amount of acids from 50% and 25% acid solutions respectively.

As per the question

50% of x + 25% of y = 40% of 10

⇒ 0.50x + 0.25y = 4

⇒ 2x + y = 16 ………(i)

Since, the total volume is 10 liters, so

x + y = 10

Subtracting (ii) from (i), we get

x = 6

Now, putting x = 6 in (ii), we have

6 + y = 10 ⇒ y = 4

Hence, volume of 50% acid solution = 6litres and volume of 25% acid solution = 4litres.