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A cheetah starts from rest,and accelerates at 2 meters per second square for 10 seconds.calculate the final velocity and the distance traveled |
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Answer» Answer: ) acceleration = a = 2m/s² starting velocity = u = 0m/s final velocity = V = ? time = t = 10 sec a = v-u/t 2 = v-0/10 2×10 = v 20 m/s = v final velocity = v = 20m/s b) velocity = v = 20m/s time = t = 10 secl distance = d = ? v = d/t v × t = d 20×10 = d 200 m = d/ the distance TRAVELED is = d = 200 metre Click to let others KNOW, how helpful is it Read more on Brainly.in - brainly.in/question/3373390#readmore Step-by-step explanation: |
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