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A charged particle (charge `q`) is moving in a circle of radius `R` with unifrom speed `v`. The associated magnetic moment `mu` is given byA. `(qvR)/2`B. `qvR^(2)`C. `(qvR^(2))/2`D. qvR |
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Answer» Correct Answer - A As revolving charge is equivalent to a current, so, `i=qf=qxx(omega)/(2pi)` But `omega=V/R` Where R is radius of circle and v is uniform speed of charged particle. Therefore, `i=(qv)/(2piR)` Now, magnetic moment associated with charged particle is given by `mu=IA=IxxpiR^(2)` `mu=(qv)/(2piR)xxpiR^(2)=1/2 qvR` |
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