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A charged particle (charge `q`) is moving in a circle of radius `R` with unifrom speed `v`. The associated magnetic moment `mu` is given byA. `(qvR)/(2)`B. `qvR^(2)`C. `(qvR^(2))/(2)`D. `qvR` |
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Answer» Correct Answer - A As revolving charge is equivalent to a current, so `I = af = q xx (omega)/(2pi)` But `omega = (v)/(R )` where `R` is radius of circle and `v` is unifrom speed of charged particle. Therefore, `I = (qv)/(2pi R)` Now, magetic moment associated with charged particles is given by `mu = IA = I xx pi R^(2)` or `mu = (qv)/(2piR) xx piR^(2) = (1)/(2)qvR` |
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