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A charged capacitor discharges through a resistance R with time constant τ. The two are now placed in series across an AC source of angular frequency ω = 1/τ The impedance of the circuit will be(a) R/√2(b) R(c) √2R(d) 2R |
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Answer» Correct Answer is: (c) √2R τ = RC ∴ ω = 1/RC Z = √(R2 + (1/ωC)2 = √(R2 + R2) = √2R |
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