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A charged belt 60 cm wide, travels at `20 ms^(-1)` between a source of charge and a sphere. The belt carries charges into the sphere at a rate corresponding to `120 mu A`. Calculate the surface charge density of the belt. |
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Answer» Here, width of belt, `w = 60 cm = 0.60 m` , Speed of belt, `v = 20 ms^(-1)` Current `I =` change added per second `= 120 mu A = 120 xx 10^(-6)A` Area of the belt moved per second, `A = wv` Charge density, `sigma = I/A = I/w v = (120 xx 10^(-6))/(0.60 xx 20)` `= 10^(-5) Cm^(-2)` |
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