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A charge of 5000 coloumb flows through a conductor for 2 hour and 30 minutes find themagnitude of current flowing through the conductor |
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Answer» Answer: CURRENT ( i ) = 0.55 Ampere Explanation: ★ CURRENT ELECTRICITY ★ GIVEN ; ★ CHARGE ( Q ) = 5000 C ★ TIME ( T ) = 2hr 30 min. » CURRENT ( i ) = ??? _________WE KNOW THAT ; _______ ★ CURRENT ( i ) = CHARGE (Q) / TIME (T) » i = Q / T » i = 5000 / 2 hour 30 min. » i = 5000 / 150 min. » i = 5000 / 150 × 60 seconds » i = 5000 / 9000 ★ » i = 0.55 Ampere « ★ ________________________________________ ANSWER :- Current FLOWING in Time " t " at charge of 5000 COULOMB is ; ★ i = 0.55 Ampere ★ |
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