A certain type of antifreeze freezes at -55°C. It boils at 113°C. Wh – InterviewSolution

1.

A certain type of antifreeze freezes at -55°C. It boils at 113°C. Which expression represents the difference between the two temperatures?

Answer»

ong>Answer:

the diff in TEMPERATURE is 168

Step-by-step EXPLANATION:

so here it goes

113 - (-55) = 113 + 55= 168 DEGREE

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