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A certain reaction is 50 % complete in 20 minutes at 300k and same reaction is again 50% complete in 5 minutes at 350k. Calculate the activation energy if the reaction is of 1st order |
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Answer» in reaction is 50% COMPLETE in 20 MINUTES at 300 K and the same reaction is again 50% complete in 5 minutes at 350 K. Calculate the activation energy if it is a FIRST ORDER reaction. [R = 8.314 J K–1 mol–1, log 4 = 0.602]. ... i.e., the rate of reaction will become 8 times the rate as in (1). |
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