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A certain number of two digits is four times the sum of the digits. If 9 is added to the number the digits in the number are reversed, then the number is ………………… A) 13 B) 23 C) 12 D) 14 |
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Answer» Correct option is (C) 12 Let the two-digit number be ab whose unit digit is b and ten's digit is a. \(\therefore\) Required number is ab = 10a + b _________(1) Reversed number is ba = 10b + a _________(2) Sum of digits = a + b According to given conditions, we have 10a + b = 4 (a+b) and 10a + b + 9 = 10b + a \(\Rightarrow\) 6a - 3b = 0 and 9a - 9b + 9 = 0 \(\Rightarrow\) 2a - b = 0 _________(3) and a - b + 1 = 0 _________(4) Subtract equation (4) from (3), we get (2a - b) - (a - b + 1) = 0 - 0 \(\Rightarrow\) a - 1 = 0 \(\Rightarrow\) a = 1 \(\therefore\) b = 2a = 2 (From (3)) \(\therefore\) Required number is ab = 12. (From (1)) Correct option is C) 12 |
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