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A certain number of spherical drops of a liquid of a liquid of radius r coalesce to form a single drop of radius R and volume V. if T is the surface tension of the liquid, then |
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Answer» `"ENERGY"=4VT(1/R-1/R)"is released"` `A_i=nxx4pir^2=(V)/(4/3 PI r^3)4pir^2=(3V)/( r)` Hence, energy released `=(A_i-A_f)T=3VT(1/r-1/R)` |
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