1.

A certain number of spherical drops of a liquid of a liquid of radius r coalesce to form a single drop of radius R and volume V. if T is the surface tension of the liquid, then

Answer»

`"ENERGY"=4VT(1/R-1/R)"is released"`
`"energy"=3VT(1/r+1/R)"is absorbed"`
`"energy"=3VT(1/r-1/R)"is released"`
energy is NEITHER released nor absorbed.

Solution :`A_f=4piR^2=3/34pi(R^3)/( R)=(3V)/(R )`
`A_i=nxx4pir^2=(V)/(4/3 PI r^3)4pir^2=(3V)/( r)`
Hence, energy released `=(A_i-A_f)T=3VT(1/r-1/R)`


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