A certain mass of gas occupies a volume of 2 litres at pressure of 1 atmospheres and a temperature of 27°C. Keeping pressure constant the volume would be doubled by raising the temperature to?

A certain mass of gas occupies a volume of 2 litres at pressure of 1 a

1.	A certain mass of gas occupies a volume of 2 litres at pressure of 1 atmospheres and a temperature of 27°C. Keeping pressure constant the volume would be doubled by raising the temperature to?
Answer» :-Required temperature is 327°C .Explanation :-We have :-→ Initial volume (V₁) = 2 L→ Initial temperature (T₁) = 27°C→ Final volume (V₂) = 2(2) = 4 L→ Pressure REMAINS CONSTANT (1 atm) .________________________________Firstly, LET's CONVERT the initial temperature from °C to K .⇒ 0°C = 273 K⇒ 27°C = 273 + 27⇒ 300 KNow according to Charle's Law, the required temperature will be GIVEN by :-V₁/T₁ = V₂/T₂⇒ 2/300 = 4/T₂⇒ 2T₂ = 4(300)⇒ T₂ = 1200/2⇒ T₂ = 600 K________________________________Required temperature in °C is :-⇒ 273 K = 0°C⇒ 600 K = (600 - 273)°C⇒ 327°C