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A certain gas takes three times as long to effuse out as helium.Its molecular mass will be..? |
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Answer» Here is your ANSWEREXPLANATION:GRAHAM’s law of DIFFUSION - \dpi{100} r_{1}/r_{2}=\sqrt{M_{1}/M_{2}} where r is rate of diffusion of gas , M is molar mass. - As per graham's law of diffusion \frac{r_{1}}{r_{2}}=\sqrt{\frac{M_{2}}{M_{1}}} given that \frac{r_{1}}{r_{2}}={\frac{1}{3}} M_{2}=4 \Rightarrow \frac{1}{3}=\sqrt{\frac{4}{M_{1}}} \Rightarrow \frac{1}{9}={\frac{4}{M_{1}}} \Rightarrow M_{1}=4\times 9 = 36 |
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