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A certain charge Q is divided at first into two parts,(q) and (Q-q). Later on the charges are placed at acertain distance. If the force of interaction betweenthe two charges is maximum then- |
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Answer» let parts are sepereted at a distance of d so repulsion force F= k q(Q-q)/d2 here Q and d are constant so for maximum force differentiate the force w.r.t q dF/dq = k/d2[Q -2q] for maximum force dF/dq=0 Q-2q=0 Q/q =2 |
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