1.

A certain acid-base indicator is red in acid solution and blue in basic medium. At pH=5 75% of the indictor is present in the solution in its blue form. Calculate the pH at which indicator shows 90% red form ?

Answer»


Solution :`K_(sp) = [Mg^(+)][OH^(-2)]`
`[oH^(-)]=SQRT((2.5xx10^(-11))/0.01)=5xx10^(-5)`
`K_(B)=([NH_(4)^(+)][OH^(-)])/([NH_(3)])`
So `[NH_(4)^(+)]=0.04M`


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