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A centre zero galvanometer is connected in series with a switch and a battery . When the switch is closed and opened periodically (nearly about 4 times/sec) its needle |
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Answer» reads always zero `thereforeI = (tau_n)/(n AB)=(18xx10^-5xx10^-2)/(60xx6xx10^-4xx500xx10^-4)` `=10^-3A` . |
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