A carof mass 1500 kg is moving with a speed of 12.5 ms^(-1) on a circular path of radius 20 mon a level raod what should be the frictional force between the car and the raod so that the car does not slip what should be thevalueof the coefficent of friction to attain this force

A carof mass 1500 kg is moving with a speed of 12.5 ms^(-1) on a circu

1.	A carof mass 1500 kg is moving with a speed of 12.5 ms^(-1) on a circular path of radius 20 mon a level raod what should be the frictional force between the car and the raod so that the car does not slip what should be thevalueof the coefficent of friction to attain this force
Answer» Solution :Given `m= 15000 KG` `v=12.5 MS^(-1)` `r=25 m` Frictionforce = Requiredcentripetalforce or`f= (mv^(2))/(r ) = (15000 xx 12.5 xx 12.5)/(20)` `=1.172 xx 10^(4) N` But `f= muR =MU MG` coefficientof friction `mu = (f )/(mg ) =- (1.172 xx 10^(4))/( 1500 xx 9.8 ) = 0.8`