A Carnot engine will sink temperature at 17^(@)C has 50% efficiency. By now much should its source temperature by changed to increase its efficiency to 60% ?

A Carnot engine will sink temperature at 17^(@)C has 50% efficiency. B

1.	A Carnot engine will sink temperature at 17^(@)C has 50% efficiency. By now much should its source temperature by changed to increase its efficiency to 60% ?
Answer» 225 K `128^(@)C` 580 K 145 K Solution :`eta = 1 - (T_(2))/(T_(1))` INITIALLY, `(50)/(100) = 1 - (273 + 17)/(T_(1))` or `(290)/(T_(1)) = (1)/(2)` or `T_(1) = 580 K` Finally, `(60)/(100) = 1 - (273 + 17)/(T._(1))` or `(290)/(T._(1)) = (2)/(5)` or `T._(1) = 725 K` `:.` Change in source TEMPERATURE `= (725 - 580) K = 145 K`