A Carnot engine takes 3 xx 10^(6) cal of heat from a reservoir at 627^(@)C and gives it to a sink 27^(@)C. The work done by the engine is

A Carnot engine takes 3 xx 10^(6) cal of heat from a reservoir at 627^

1.	A Carnot engine takes 3 xx 10^(6) cal of heat from a reservoir at 627^(@)C and gives it to a sink 27^(@)C. The work done by the engine is
Answer» `4.2 xx 10^(6) J` `8.4 xx 10^(6) J` `16.8 xx 10^(6) J` zero Solution :Here, `T_(1) = 627 + 273 = 900 K, Q_(1) = 3 xx 10^(6) cal` `T_(2) = 27 + 273 = 300 K` As `(Q_(1))/(Q_(2)) = (T_(1))/(T_(2)) :. Q_(2) = (T_(2))/(T_(1)) xx Q_(1) = (300)/(900) xx 3 xx 10^(6) = 1 xx 10^(6) cal` `:.` Work done `= Q_(1) - Q_(2) = 3 xx 10^(6) - 1 xx 10^(6) = 2 xx 10^(6) cal` `= 2 xx 4.2 xx 10^(6) J = 8.4 xx 10^(6) J`