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a carnot engine has an efficiency of 50% when its sink temperature is 27°c what must be the change in its source temperature for increasing its efficiency to 60%? |
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Answer» TAKING the Sink Temperature(T2) = 27 degree celsius = 300 kelvin Efficiency(eta) be 25% = .25 Source Temperature(T1) = ? Efficiency= (T1 - T2) / T1 Efficiency= 1 -T2/T1 T2/T1 = 1 - Efficiency T1 = T2/(1 - Efficiency) T1= 300/(1-.25) T1 = 400 kelvin = 127 degree celsius |
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