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A carbon resistor of `(47 +- 4.7) k Omega` is to be marked with rings of different colours for its identification. The colour code sequence will beA. Green - Orange - Voilet - GoldB. Violet - Yellow - Orange - SilverC. Yellow- Green - Violet - GoldD. Yellow - Violet - Orange - Silver |
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Answer» Correct Answer - D (d) `R = (47 +- 4.7) xx 10^(3) implies R = 47 xx 10^(3) +- 10^(3) % Omega` As per color code, 3- Orange - Violet - Orange, 4 - Yellow, 7 - Violet 10% silver So current sequence is Yellow - violet - Orange - Silver |
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