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a car weighing 1000kg is going up an incline with a slope of 2 in 25 at a steady speed of 18kmph .If g=10the power of its engine is |
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Answer» slope of inclined plane , tanθ = 2/25 so, sinθ = 2/√(25² + 2²) = 2/√629 now, weight of car along inclined plane, F = mgsinθ here, m = 1000kg, g = 10m/s² and sinθ = 2/√(629) so, F = 1000 × 10 × 2/√(629) ≈ 797.452 N VELOCITY of car along plane , v = 18km/h = 18 × 5/18 = 5m/s so, power of its ENGINE = weight of car along plane × velocity of car along plane. = F × v = 797.452 × 5 W = 3,987.26 W = 3.98726 kW ≈ 4 kW hence, power of car engine = 4kW |
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