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A car weighing 1000kg and travelling at 30m/s stop at a distance of 50m decelerating uniformly what is the work done by the brakes |
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Answer» 450000JExplanation:because, F=mabut 2aS=v^2-u^2 2.a.50=0-900 a=-900/2.50 a=-9-ve sign SHOW deaccelerationtherefore, F=m.a=1000×9=9000 WORK done=F.s=9000×50=45kJ Hope it helps you and PLS mark my ans as BRAINLIST |
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