A car Travels 90 metres due north in 15 seconds then car turns around

1.	A car Travels 90 metres due north in 15 seconds then car turns around the and travels 40 metres deu south in 5 second what is the magnitude of the average velocity of the car during this 20 sec interval
Answer» Answer: 2.5 m/s Explanation: Displacement of car = Shortest distance between initial and FINAL POSITION = 90 m - 40 m = 50 m Average VELOCITY = Total displacement / Total TIME = (50 m) / (20 s) = 2.5 m/s

A car Travels 90 metres due north in 15 seconds then car turns around the and travels 40 metres deu south in 5 second what is the magnitude of the average velocity of the car during this 20 sec interval

Answer»

Answer:

2.5 m/s

Explanation:

Displacement of car = Shortest distance between initial and FINAL POSITION

= 90 m - 40 m

= 50 m

Average VELOCITY = Total displacement / Total TIME

= (50 m) / (20 s)

= 2.5 m/s

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A car Travels 90 metres due north in 15 seconds then car turns around the and travels 40 metres deu south in 5 second what is the magnitude of the average velocity of the car during this 20 sec interval​

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A car Travels 90 metres due north in 15 seconds then car turns around the and travels 40 metres deu south in 5 second what is the magnitude of the average velocity of the car during this 20 sec interval