a car travels 30km at a uniform speed of 40km/hr and the next 30km at

1.	a car travels 30km at a uniform speed of 40km/hr and the next 30km at a uniform speed of 20km/hr. find its overage speed. with full explanation?
Answer» Given : ▪ A car TRAVELS first 30km at a speed of 40kmph and last 30kmph at a speed of 20kmph. To FIND : ▪ Average speed of car during the whole journey. Concept : ☞ Average speed is defined as the ratio of total distanve travelled to the total time taken. ☞ It is a SCALAR quantity. ☞ It has only magnitude. ☞ It can't be NEGATIVE or zero. ☞ SI unit : m/s Calculation : → VAV = (d1+d2)/(t1+t2) → Vav = (d1+d2)/[(d1/V1)+(d2/V2)] → Vav = (30+30)/[(30/40)+(30/20)] → Vav = 2×40×20/(40+20) → Vav = 1600/60 → Vav = 26.67kmph

a car travels 30km at a uniform speed of 40km/hr and the next 30km at a uniform speed of 20km/hr. find its overage speed. with full explanation?

Answer»

Given :

▪ A car TRAVELS first 30km at a speed of 40kmph and last 30kmph at a speed of 20kmph.

To FIND :

▪ Average speed of car during the whole journey.

Concept :

☞ Average speed is defined as the ratio of total distanve travelled to the total time taken.

☞ It is a SCALAR quantity.

☞ It has only magnitude.

☞ It can't be NEGATIVE or zero.

☞ SI unit : m/s

Calculation :

→ VAV = (d1+d2)/(t1+t2)

→ Vav = (d1+d2)/[(d1/V1)+(d2/V2)]

→ Vav = (30+30)/[(30/40)+(30/20)]

→ Vav = 2×40×20/(40+20)

→ Vav = 1600/60

→ Vav = 26.67kmph

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a car travels 30km at a uniform speed of 40km/hr and the next 30km at a uniform speed of 20km/hr. find its overage speed. with full explanation?​